Foundations of Algebraic Geometry Bonus Handout: Proofs of “hartogs” and Krull
نویسنده
چکیده
where Idn is the n×n identity matrix in R, andA = (aij). We can’t quite invert this matrix, but we almost can. Recall that any n×nmatrixM has an adjoint matrix adj(M) such that adj(M)M = det(M)Idn. The coefficients of adj(M) are polynomials in the coefficients of M. (You’ve likely seen this in the form of a formula for M when there is an inverse.) Multiplying both sides of (1) on the left by adj(M), we obtain
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